Optimal. Leaf size=167 \[ \frac{a \left (C \left (a^2+4 b^2\right )+6 A b^2\right ) \sin (c+d x)}{2 d}+\frac{b \left (2 a^2 C+b^2 (4 A+3 C)\right ) \sin (c+d x) \cos (c+d x)}{8 d}+\frac{1}{8} b x \left (12 a^2 (2 A+C)+b^2 (4 A+3 C)\right )+\frac{a^3 A \tanh ^{-1}(\sin (c+d x))}{d}+\frac{a C \sin (c+d x) (a+b \cos (c+d x))^2}{4 d}+\frac{C \sin (c+d x) (a+b \cos (c+d x))^3}{4 d} \]
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Rubi [A] time = 0.542427, antiderivative size = 167, normalized size of antiderivative = 1., number of steps used = 6, number of rules used = 6, integrand size = 31, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.194, Rules used = {3050, 3049, 3033, 3023, 2735, 3770} \[ \frac{a \left (C \left (a^2+4 b^2\right )+6 A b^2\right ) \sin (c+d x)}{2 d}+\frac{b \left (2 a^2 C+b^2 (4 A+3 C)\right ) \sin (c+d x) \cos (c+d x)}{8 d}+\frac{1}{8} b x \left (12 a^2 (2 A+C)+b^2 (4 A+3 C)\right )+\frac{a^3 A \tanh ^{-1}(\sin (c+d x))}{d}+\frac{a C \sin (c+d x) (a+b \cos (c+d x))^2}{4 d}+\frac{C \sin (c+d x) (a+b \cos (c+d x))^3}{4 d} \]
Antiderivative was successfully verified.
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Rule 3050
Rule 3049
Rule 3033
Rule 3023
Rule 2735
Rule 3770
Rubi steps
\begin{align*} \int (a+b \cos (c+d x))^3 \left (A+C \cos ^2(c+d x)\right ) \sec (c+d x) \, dx &=\frac{C (a+b \cos (c+d x))^3 \sin (c+d x)}{4 d}+\frac{1}{4} \int (a+b \cos (c+d x))^2 \left (4 a A+b (4 A+3 C) \cos (c+d x)+3 a C \cos ^2(c+d x)\right ) \sec (c+d x) \, dx\\ &=\frac{a C (a+b \cos (c+d x))^2 \sin (c+d x)}{4 d}+\frac{C (a+b \cos (c+d x))^3 \sin (c+d x)}{4 d}+\frac{1}{12} \int (a+b \cos (c+d x)) \left (12 a^2 A+3 a b (8 A+5 C) \cos (c+d x)+3 \left (2 a^2 C+b^2 (4 A+3 C)\right ) \cos ^2(c+d x)\right ) \sec (c+d x) \, dx\\ &=\frac{b \left (2 a^2 C+b^2 (4 A+3 C)\right ) \cos (c+d x) \sin (c+d x)}{8 d}+\frac{a C (a+b \cos (c+d x))^2 \sin (c+d x)}{4 d}+\frac{C (a+b \cos (c+d x))^3 \sin (c+d x)}{4 d}+\frac{1}{24} \int \left (24 a^3 A+3 b \left (12 a^2 (2 A+C)+b^2 (4 A+3 C)\right ) \cos (c+d x)+12 a \left (6 A b^2+\left (a^2+4 b^2\right ) C\right ) \cos ^2(c+d x)\right ) \sec (c+d x) \, dx\\ &=\frac{a \left (6 A b^2+\left (a^2+4 b^2\right ) C\right ) \sin (c+d x)}{2 d}+\frac{b \left (2 a^2 C+b^2 (4 A+3 C)\right ) \cos (c+d x) \sin (c+d x)}{8 d}+\frac{a C (a+b \cos (c+d x))^2 \sin (c+d x)}{4 d}+\frac{C (a+b \cos (c+d x))^3 \sin (c+d x)}{4 d}+\frac{1}{24} \int \left (24 a^3 A+3 b \left (12 a^2 (2 A+C)+b^2 (4 A+3 C)\right ) \cos (c+d x)\right ) \sec (c+d x) \, dx\\ &=\frac{1}{8} b \left (12 a^2 (2 A+C)+b^2 (4 A+3 C)\right ) x+\frac{a \left (6 A b^2+\left (a^2+4 b^2\right ) C\right ) \sin (c+d x)}{2 d}+\frac{b \left (2 a^2 C+b^2 (4 A+3 C)\right ) \cos (c+d x) \sin (c+d x)}{8 d}+\frac{a C (a+b \cos (c+d x))^2 \sin (c+d x)}{4 d}+\frac{C (a+b \cos (c+d x))^3 \sin (c+d x)}{4 d}+\left (a^3 A\right ) \int \sec (c+d x) \, dx\\ &=\frac{1}{8} b \left (12 a^2 (2 A+C)+b^2 (4 A+3 C)\right ) x+\frac{a^3 A \tanh ^{-1}(\sin (c+d x))}{d}+\frac{a \left (6 A b^2+\left (a^2+4 b^2\right ) C\right ) \sin (c+d x)}{2 d}+\frac{b \left (2 a^2 C+b^2 (4 A+3 C)\right ) \cos (c+d x) \sin (c+d x)}{8 d}+\frac{a C (a+b \cos (c+d x))^2 \sin (c+d x)}{4 d}+\frac{C (a+b \cos (c+d x))^3 \sin (c+d x)}{4 d}\\ \end{align*}
Mathematica [A] time = 0.561259, size = 180, normalized size = 1.08 \[ \frac{4 b (c+d x) \left (12 a^2 (2 A+C)+b^2 (4 A+3 C)\right )+8 a \left (4 a^2 C+12 A b^2+9 b^2 C\right ) \sin (c+d x)+8 b \left (C \left (3 a^2+b^2\right )+A b^2\right ) \sin (2 (c+d x))-32 a^3 A \log \left (\cos \left (\frac{1}{2} (c+d x)\right )-\sin \left (\frac{1}{2} (c+d x)\right )\right )+32 a^3 A \log \left (\sin \left (\frac{1}{2} (c+d x)\right )+\cos \left (\frac{1}{2} (c+d x)\right )\right )+8 a b^2 C \sin (3 (c+d x))+b^3 C \sin (4 (c+d x))}{32 d} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.049, size = 252, normalized size = 1.5 \begin{align*}{\frac{A{b}^{3}\cos \left ( dx+c \right ) \sin \left ( dx+c \right ) }{2\,d}}+{\frac{A{b}^{3}x}{2}}+{\frac{A{b}^{3}c}{2\,d}}+{\frac{C{b}^{3}\sin \left ( dx+c \right ) \left ( \cos \left ( dx+c \right ) \right ) ^{3}}{4\,d}}+{\frac{3\,C{b}^{3}\cos \left ( dx+c \right ) \sin \left ( dx+c \right ) }{8\,d}}+{\frac{3\,{b}^{3}Cx}{8}}+{\frac{3\,C{b}^{3}c}{8\,d}}+3\,{\frac{aA{b}^{2}\sin \left ( dx+c \right ) }{d}}+{\frac{C\sin \left ( dx+c \right ) \left ( \cos \left ( dx+c \right ) \right ) ^{2}a{b}^{2}}{d}}+2\,{\frac{Ca{b}^{2}\sin \left ( dx+c \right ) }{d}}+3\,A{a}^{2}bx+3\,{\frac{A{a}^{2}bc}{d}}+{\frac{3\,{a}^{2}bC\cos \left ( dx+c \right ) \sin \left ( dx+c \right ) }{2\,d}}+{\frac{3\,{a}^{2}bCx}{2}}+{\frac{3\,{a}^{2}bCc}{2\,d}}+{\frac{A{a}^{3}\ln \left ( \sec \left ( dx+c \right ) +\tan \left ( dx+c \right ) \right ) }{d}}+{\frac{{a}^{3}C\sin \left ( dx+c \right ) }{d}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A] time = 0.99887, size = 225, normalized size = 1.35 \begin{align*} \frac{96 \,{\left (d x + c\right )} A a^{2} b + 24 \,{\left (2 \, d x + 2 \, c + \sin \left (2 \, d x + 2 \, c\right )\right )} C a^{2} b - 32 \,{\left (\sin \left (d x + c\right )^{3} - 3 \, \sin \left (d x + c\right )\right )} C a b^{2} + 8 \,{\left (2 \, d x + 2 \, c + \sin \left (2 \, d x + 2 \, c\right )\right )} A b^{3} +{\left (12 \, d x + 12 \, c + \sin \left (4 \, d x + 4 \, c\right ) + 8 \, \sin \left (2 \, d x + 2 \, c\right )\right )} C b^{3} + 32 \, A a^{3} \log \left (\sec \left (d x + c\right ) + \tan \left (d x + c\right )\right ) + 32 \, C a^{3} \sin \left (d x + c\right ) + 96 \, A a b^{2} \sin \left (d x + c\right )}{32 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 1.60282, size = 354, normalized size = 2.12 \begin{align*} \frac{4 \, A a^{3} \log \left (\sin \left (d x + c\right ) + 1\right ) - 4 \, A a^{3} \log \left (-\sin \left (d x + c\right ) + 1\right ) +{\left (12 \,{\left (2 \, A + C\right )} a^{2} b +{\left (4 \, A + 3 \, C\right )} b^{3}\right )} d x +{\left (2 \, C b^{3} \cos \left (d x + c\right )^{3} + 8 \, C a b^{2} \cos \left (d x + c\right )^{2} + 8 \, C a^{3} + 8 \,{\left (3 \, A + 2 \, C\right )} a b^{2} +{\left (12 \, C a^{2} b +{\left (4 \, A + 3 \, C\right )} b^{3}\right )} \cos \left (d x + c\right )\right )} \sin \left (d x + c\right )}{8 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [B] time = 1.33711, size = 679, normalized size = 4.07 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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